# Line slope calculator 9x-10y=-10

**Straight line given by points A[0; 1] and B[10; 10]**

## Calculation:

**Slope-intercept form of line:**y = 0.9x+1

**Canonical form of the line equation:**9x-10y+10 = 0

**Parametric form of the line equation:**

x = 10t

y = 9t+1 ; t ∈ R

**Slope:**m = 0.9

**Slope angle of line: φ =**41°59'14″ = 0.7328 rad

**X intercept:**x

_{0}= -1.1111

**Y intercept:**y

_{0}= q = 1

**Distance line from the origin:**d

_{0}= 0.7433

**The length of the segment AB: |AB| =**13.4536

**Vector: AB =**(10; 9)

**Normal vector: n =**(9; -10)

**Midpoint of the segment AB: M =**[5; 5.5]

**Perpendicular Bisector equation:**10x+9y-99.5 = 0

**Vector OA = (0; 1) ; |OA| = 1**

**Vector OB = (10; 10) ; |OB| = 14.1421**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 45° = 0.7854 rad**